3.155 \(\int \frac{A+B \log (e (\frac{a+b x}{c+d x})^n)}{(a g+b g x) (c i+d i x)^3} \, dx\)

Optimal. Leaf size=254 \[ \frac{b^2 \log \left (\frac{a+b x}{c+d x}\right ) \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )}{g i^3 (b c-a d)^3}+\frac{d^2 (a+b x)^2 \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )}{2 g i^3 (c+d x)^2 (b c-a d)^3}-\frac{2 b d (a+b x) \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )}{g i^3 (c+d x) (b c-a d)^3}-\frac{b^2 B n \log ^2\left (\frac{a+b x}{c+d x}\right )}{2 g i^3 (b c-a d)^3}-\frac{B n \left (4 b-\frac{d (a+b x)}{c+d x}\right )^2}{4 g i^3 (b c-a d)^3} \]

[Out]

-(B*n*(4*b - (d*(a + b*x))/(c + d*x))^2)/(4*(b*c - a*d)^3*g*i^3) + (d^2*(a + b*x)^2*(A + B*Log[e*((a + b*x)/(c
+ d*x))^n]))/(2*(b*c - a*d)^3*g*i^3*(c + d*x)^2) - (2*b*d*(a + b*x)*(A + B*Log[e*((a + b*x)/(c + d*x))^n]))/(
(b*c - a*d)^3*g*i^3*(c + d*x)) + (b^2*(A + B*Log[e*((a + b*x)/(c + d*x))^n])*Log[(a + b*x)/(c + d*x)])/((b*c -
a*d)^3*g*i^3) - (b^2*B*n*Log[(a + b*x)/(c + d*x)]^2)/(2*(b*c - a*d)^3*g*i^3)

________________________________________________________________________________________

Rubi [C]  time = 0.868867, antiderivative size = 557, normalized size of antiderivative = 2.19, number of steps used = 26, number of rules used = 11, integrand size = 43, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.256, Rules used = {2528, 2524, 2418, 2390, 2301, 2394, 2393, 2391, 2525, 12, 44} \[ \frac{b^2 B n \text{PolyLog}\left (2,-\frac{d (a+b x)}{b c-a d}\right )}{g i^3 (b c-a d)^3}+\frac{b^2 B n \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )}{g i^3 (b c-a d)^3}+\frac{b^2 \log (a+b x) \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )}{g i^3 (b c-a d)^3}-\frac{b^2 \log (c+d x) \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )}{g i^3 (b c-a d)^3}+\frac{b \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )}{g i^3 (c+d x) (b c-a d)^2}+\frac{B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A}{2 g i^3 (c+d x)^2 (b c-a d)}-\frac{b^2 B n \log ^2(a+b x)}{2 g i^3 (b c-a d)^3}-\frac{b^2 B n \log ^2(c+d x)}{2 g i^3 (b c-a d)^3}-\frac{3 b^2 B n \log (a+b x)}{2 g i^3 (b c-a d)^3}+\frac{3 b^2 B n \log (c+d x)}{2 g i^3 (b c-a d)^3}+\frac{b^2 B n \log (c+d x) \log \left (-\frac{d (a+b x)}{b c-a d}\right )}{g i^3 (b c-a d)^3}+\frac{b^2 B n \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{g i^3 (b c-a d)^3}-\frac{3 b B n}{2 g i^3 (c+d x) (b c-a d)^2}-\frac{B n}{4 g i^3 (c+d x)^2 (b c-a d)} \]

Antiderivative was successfully verified.

[In]

Int[(A + B*Log[e*((a + b*x)/(c + d*x))^n])/((a*g + b*g*x)*(c*i + d*i*x)^3),x]

[Out]

-(B*n)/(4*(b*c - a*d)*g*i^3*(c + d*x)^2) - (3*b*B*n)/(2*(b*c - a*d)^2*g*i^3*(c + d*x)) - (3*b^2*B*n*Log[a + b*
x])/(2*(b*c - a*d)^3*g*i^3) - (b^2*B*n*Log[a + b*x]^2)/(2*(b*c - a*d)^3*g*i^3) + (A + B*Log[e*((a + b*x)/(c +
d*x))^n])/(2*(b*c - a*d)*g*i^3*(c + d*x)^2) + (b*(A + B*Log[e*((a + b*x)/(c + d*x))^n]))/((b*c - a*d)^2*g*i^3*
(c + d*x)) + (b^2*Log[a + b*x]*(A + B*Log[e*((a + b*x)/(c + d*x))^n]))/((b*c - a*d)^3*g*i^3) + (3*b^2*B*n*Log[
c + d*x])/(2*(b*c - a*d)^3*g*i^3) + (b^2*B*n*Log[-((d*(a + b*x))/(b*c - a*d))]*Log[c + d*x])/((b*c - a*d)^3*g*
i^3) - (b^2*(A + B*Log[e*((a + b*x)/(c + d*x))^n])*Log[c + d*x])/((b*c - a*d)^3*g*i^3) - (b^2*B*n*Log[c + d*x]
^2)/(2*(b*c - a*d)^3*g*i^3) + (b^2*B*n*Log[a + b*x]*Log[(b*(c + d*x))/(b*c - a*d)])/((b*c - a*d)^3*g*i^3) + (b
^2*B*n*PolyLog[2, -((d*(a + b*x))/(b*c - a*d))])/((b*c - a*d)^3*g*i^3) + (b^2*B*n*PolyLog[2, (b*(c + d*x))/(b*
c - a*d)])/((b*c - a*d)^3*g*i^3)

Rule 2528

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*(RGx_), x_Symbol] :> With[{u = ExpandIntegrand[(a + b*Log[c*
RFx^p])^n, RGx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, p}, x] && RationalFunctionQ[RFx, x] && RationalF
unctionQ[RGx, x] && IGtQ[n, 0]

Rule 2524

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[(Log[d + e*x]*(a + b
*Log[c*RFx^p])^n)/e, x] - Dist[(b*n*p)/e, Int[(Log[d + e*x]*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x
] /; FreeQ[{a, b, c, d, e, p}, x] && RationalFunctionQ[RFx, x] && IGtQ[n, 0]

Rule 2418

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[
(a + b*Log[c*(d + e*x)^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, d, e, n}, x] && RationalFunct
ionQ[RFx, x] && IntegerQ[p]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2525

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*((d_.) + (e_.)*(x_))^(m_.), x_Symbol] :> Simp[((d + e*x)^(m
+ 1)*(a + b*Log[c*RFx^p])^n)/(e*(m + 1)), x] - Dist[(b*n*p)/(e*(m + 1)), Int[SimplifyIntegrand[((d + e*x)^(m +
1)*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && RationalFunc
tionQ[RFx, x] && IGtQ[n, 0] && (EqQ[n, 1] || IntegerQ[m]) && NeQ[m, -1]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int \frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{(155 c+155 d x)^3 (a g+b g x)} \, dx &=\int \left (\frac{b^3 \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^3 g (a+b x)}-\frac{d \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d) g (c+d x)^3}-\frac{b d \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^2 g (c+d x)^2}-\frac{b^2 d \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^3 g (c+d x)}\right ) \, dx\\ &=\frac{b^3 \int \frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{a+b x} \, dx}{3723875 (b c-a d)^3 g}-\frac{\left (b^2 d\right ) \int \frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{c+d x} \, dx}{3723875 (b c-a d)^3 g}-\frac{(b d) \int \frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{(c+d x)^2} \, dx}{3723875 (b c-a d)^2 g}-\frac{d \int \frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{(c+d x)^3} \, dx}{3723875 (b c-a d) g}\\ &=\frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{7447750 (b c-a d) g (c+d x)^2}+\frac{b \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^2 g (c+d x)}+\frac{b^2 \log (a+b x) \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^3 g}-\frac{b^2 \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}-\frac{\left (b^2 B n\right ) \int \frac{(c+d x) \left (-\frac{d (a+b x)}{(c+d x)^2}+\frac{b}{c+d x}\right ) \log (a+b x)}{a+b x} \, dx}{3723875 (b c-a d)^3 g}+\frac{\left (b^2 B n\right ) \int \frac{(c+d x) \left (-\frac{d (a+b x)}{(c+d x)^2}+\frac{b}{c+d x}\right ) \log (c+d x)}{a+b x} \, dx}{3723875 (b c-a d)^3 g}-\frac{(b B n) \int \frac{b c-a d}{(a+b x) (c+d x)^2} \, dx}{3723875 (b c-a d)^2 g}-\frac{(B n) \int \frac{b c-a d}{(a+b x) (c+d x)^3} \, dx}{7447750 (b c-a d) g}\\ &=\frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{7447750 (b c-a d) g (c+d x)^2}+\frac{b \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^2 g (c+d x)}+\frac{b^2 \log (a+b x) \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^3 g}-\frac{b^2 \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}-\frac{(B n) \int \frac{1}{(a+b x) (c+d x)^3} \, dx}{7447750 g}-\frac{\left (b^2 B n\right ) \int \left (\frac{b \log (a+b x)}{a+b x}-\frac{d \log (a+b x)}{c+d x}\right ) \, dx}{3723875 (b c-a d)^3 g}+\frac{\left (b^2 B n\right ) \int \left (\frac{b \log (c+d x)}{a+b x}-\frac{d \log (c+d x)}{c+d x}\right ) \, dx}{3723875 (b c-a d)^3 g}-\frac{(b B n) \int \frac{1}{(a+b x) (c+d x)^2} \, dx}{3723875 (b c-a d) g}\\ &=\frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{7447750 (b c-a d) g (c+d x)^2}+\frac{b \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^2 g (c+d x)}+\frac{b^2 \log (a+b x) \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^3 g}-\frac{b^2 \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}-\frac{(B n) \int \left (\frac{b^3}{(b c-a d)^3 (a+b x)}-\frac{d}{(b c-a d) (c+d x)^3}-\frac{b d}{(b c-a d)^2 (c+d x)^2}-\frac{b^2 d}{(b c-a d)^3 (c+d x)}\right ) \, dx}{7447750 g}-\frac{\left (b^3 B n\right ) \int \frac{\log (a+b x)}{a+b x} \, dx}{3723875 (b c-a d)^3 g}+\frac{\left (b^3 B n\right ) \int \frac{\log (c+d x)}{a+b x} \, dx}{3723875 (b c-a d)^3 g}+\frac{\left (b^2 B d n\right ) \int \frac{\log (a+b x)}{c+d x} \, dx}{3723875 (b c-a d)^3 g}-\frac{\left (b^2 B d n\right ) \int \frac{\log (c+d x)}{c+d x} \, dx}{3723875 (b c-a d)^3 g}-\frac{(b B n) \int \left (\frac{b^2}{(b c-a d)^2 (a+b x)}-\frac{d}{(b c-a d) (c+d x)^2}-\frac{b d}{(b c-a d)^2 (c+d x)}\right ) \, dx}{3723875 (b c-a d) g}\\ &=-\frac{B n}{14895500 (b c-a d) g (c+d x)^2}-\frac{3 b B n}{7447750 (b c-a d)^2 g (c+d x)}-\frac{3 b^2 B n \log (a+b x)}{7447750 (b c-a d)^3 g}+\frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{7447750 (b c-a d) g (c+d x)^2}+\frac{b \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^2 g (c+d x)}+\frac{b^2 \log (a+b x) \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^3 g}+\frac{3 b^2 B n \log (c+d x)}{7447750 (b c-a d)^3 g}+\frac{b^2 B n \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}-\frac{b^2 \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}+\frac{b^2 B n \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{3723875 (b c-a d)^3 g}-\frac{\left (b^2 B n\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,a+b x\right )}{3723875 (b c-a d)^3 g}-\frac{\left (b^2 B n\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,c+d x\right )}{3723875 (b c-a d)^3 g}-\frac{\left (b^3 B n\right ) \int \frac{\log \left (\frac{b (c+d x)}{b c-a d}\right )}{a+b x} \, dx}{3723875 (b c-a d)^3 g}-\frac{\left (b^2 B d n\right ) \int \frac{\log \left (\frac{d (a+b x)}{-b c+a d}\right )}{c+d x} \, dx}{3723875 (b c-a d)^3 g}\\ &=-\frac{B n}{14895500 (b c-a d) g (c+d x)^2}-\frac{3 b B n}{7447750 (b c-a d)^2 g (c+d x)}-\frac{3 b^2 B n \log (a+b x)}{7447750 (b c-a d)^3 g}-\frac{b^2 B n \log ^2(a+b x)}{7447750 (b c-a d)^3 g}+\frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{7447750 (b c-a d) g (c+d x)^2}+\frac{b \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^2 g (c+d x)}+\frac{b^2 \log (a+b x) \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^3 g}+\frac{3 b^2 B n \log (c+d x)}{7447750 (b c-a d)^3 g}+\frac{b^2 B n \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}-\frac{b^2 \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}-\frac{b^2 B n \log ^2(c+d x)}{7447750 (b c-a d)^3 g}+\frac{b^2 B n \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{3723875 (b c-a d)^3 g}-\frac{\left (b^2 B n\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{d x}{b c-a d}\right )}{x} \, dx,x,a+b x\right )}{3723875 (b c-a d)^3 g}-\frac{\left (b^2 B n\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{-b c+a d}\right )}{x} \, dx,x,c+d x\right )}{3723875 (b c-a d)^3 g}\\ &=-\frac{B n}{14895500 (b c-a d) g (c+d x)^2}-\frac{3 b B n}{7447750 (b c-a d)^2 g (c+d x)}-\frac{3 b^2 B n \log (a+b x)}{7447750 (b c-a d)^3 g}-\frac{b^2 B n \log ^2(a+b x)}{7447750 (b c-a d)^3 g}+\frac{A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )}{7447750 (b c-a d) g (c+d x)^2}+\frac{b \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^2 g (c+d x)}+\frac{b^2 \log (a+b x) \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right )}{3723875 (b c-a d)^3 g}+\frac{3 b^2 B n \log (c+d x)}{7447750 (b c-a d)^3 g}+\frac{b^2 B n \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}-\frac{b^2 \left (A+B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{3723875 (b c-a d)^3 g}-\frac{b^2 B n \log ^2(c+d x)}{7447750 (b c-a d)^3 g}+\frac{b^2 B n \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{3723875 (b c-a d)^3 g}+\frac{b^2 B n \text{Li}_2\left (-\frac{d (a+b x)}{b c-a d}\right )}{3723875 (b c-a d)^3 g}+\frac{b^2 B n \text{Li}_2\left (\frac{b (c+d x)}{b c-a d}\right )}{3723875 (b c-a d)^3 g}\\ \end{align*}

Mathematica [C]  time = 0.389916, size = 434, normalized size = 1.71 \[ \frac{-2 b^2 B n (c+d x)^2 \left (\log (a+b x) \left (\log (a+b x)-2 \log \left (\frac{b (c+d x)}{b c-a d}\right )\right )-2 \text{PolyLog}\left (2,\frac{d (a+b x)}{a d-b c}\right )\right )+2 b^2 B n (c+d x)^2 \left (2 \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )+\log (c+d x) \left (2 \log \left (\frac{d (a+b x)}{a d-b c}\right )-\log (c+d x)\right )\right )+4 b^2 (c+d x)^2 \log (a+b x) \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )-4 b^2 (c+d x)^2 \log (c+d x) \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )+2 (b c-a d)^2 \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )+4 b (c+d x) (b c-a d) \left (B \log \left (e \left (\frac{a+b x}{c+d x}\right )^n\right )+A\right )-B n \left (2 b^2 (c+d x)^2 \log (a+b x)+2 b (c+d x) (b c-a d)+(b c-a d)^2-2 b^2 (c+d x)^2 \log (c+d x)\right )-4 b B n (c+d x) (b (c+d x) \log (a+b x)-a d-b (c+d x) \log (c+d x)+b c)}{4 g i^3 (c+d x)^2 (b c-a d)^3} \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*Log[e*((a + b*x)/(c + d*x))^n])/((a*g + b*g*x)*(c*i + d*i*x)^3),x]

[Out]

(2*(b*c - a*d)^2*(A + B*Log[e*((a + b*x)/(c + d*x))^n]) + 4*b*(b*c - a*d)*(c + d*x)*(A + B*Log[e*((a + b*x)/(c
+ d*x))^n]) + 4*b^2*(c + d*x)^2*Log[a + b*x]*(A + B*Log[e*((a + b*x)/(c + d*x))^n]) - 4*b^2*(c + d*x)^2*(A +
B*Log[e*((a + b*x)/(c + d*x))^n])*Log[c + d*x] - 4*b*B*n*(c + d*x)*(b*c - a*d + b*(c + d*x)*Log[a + b*x] - b*(
c + d*x)*Log[c + d*x]) - B*n*((b*c - a*d)^2 + 2*b*(b*c - a*d)*(c + d*x) + 2*b^2*(c + d*x)^2*Log[a + b*x] - 2*b
^2*(c + d*x)^2*Log[c + d*x]) - 2*b^2*B*n*(c + d*x)^2*(Log[a + b*x]*(Log[a + b*x] - 2*Log[(b*(c + d*x))/(b*c -
a*d)]) - 2*PolyLog[2, (d*(a + b*x))/(-(b*c) + a*d)]) + 2*b^2*B*n*(c + d*x)^2*((2*Log[(d*(a + b*x))/(-(b*c) + a
*d)] - Log[c + d*x])*Log[c + d*x] + 2*PolyLog[2, (b*(c + d*x))/(b*c - a*d)]))/(4*(b*c - a*d)^3*g*i^3*(c + d*x)
^2)

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Maple [F]  time = 0.75, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{ \left ( bgx+ag \right ) \left ( dix+ci \right ) ^{3}} \left ( A+B\ln \left ( e \left ({\frac{bx+a}{dx+c}} \right ) ^{n} \right ) \right ) }\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A+B*ln(e*((b*x+a)/(d*x+c))^n))/(b*g*x+a*g)/(d*i*x+c*i)^3,x)

[Out]

int((A+B*ln(e*((b*x+a)/(d*x+c))^n))/(b*g*x+a*g)/(d*i*x+c*i)^3,x)

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Maxima [B]  time = 1.42133, size = 1199, normalized size = 4.72 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*((b*x+a)/(d*x+c))^n))/(b*g*x+a*g)/(d*i*x+c*i)^3,x, algorithm="maxima")

[Out]

1/2*B*((2*b*d*x + 3*b*c - a*d)/((b^2*c^2*d^2 - 2*a*b*c*d^3 + a^2*d^4)*g*i^3*x^2 + 2*(b^2*c^3*d - 2*a*b*c^2*d^2
+ a^2*c*d^3)*g*i^3*x + (b^2*c^4 - 2*a*b*c^3*d + a^2*c^2*d^2)*g*i^3) + 2*b^2*log(b*x + a)/((b^3*c^3 - 3*a*b^2*
c^2*d + 3*a^2*b*c*d^2 - a^3*d^3)*g*i^3) - 2*b^2*log(d*x + c)/((b^3*c^3 - 3*a*b^2*c^2*d + 3*a^2*b*c*d^2 - a^3*d
^3)*g*i^3))*log(e*(b*x/(d*x + c) + a/(d*x + c))^n) - 1/4*(7*b^2*c^2 - 8*a*b*c*d + a^2*d^2 + 2*(b^2*d^2*x^2 + 2
*b^2*c*d*x + b^2*c^2)*log(b*x + a)^2 + 2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*log(d*x + c)^2 + 6*(b^2*c*d - a
*b*d^2)*x + 6*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*log(b*x + a) - 2*(3*b^2*d^2*x^2 + 6*b^2*c*d*x + 3*b^2*c^2
+ 2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*log(b*x + a))*log(d*x + c))*B*n/(b^3*c^5*g*i^3 - 3*a*b^2*c^4*d*g*i^3
+ 3*a^2*b*c^3*d^2*g*i^3 - a^3*c^2*d^3*g*i^3 + (b^3*c^3*d^2*g*i^3 - 3*a*b^2*c^2*d^3*g*i^3 + 3*a^2*b*c*d^4*g*i^
3 - a^3*d^5*g*i^3)*x^2 + 2*(b^3*c^4*d*g*i^3 - 3*a*b^2*c^3*d^2*g*i^3 + 3*a^2*b*c^2*d^3*g*i^3 - a^3*c*d^4*g*i^3)
*x) + 1/2*A*((2*b*d*x + 3*b*c - a*d)/((b^2*c^2*d^2 - 2*a*b*c*d^3 + a^2*d^4)*g*i^3*x^2 + 2*(b^2*c^3*d - 2*a*b*c
^2*d^2 + a^2*c*d^3)*g*i^3*x + (b^2*c^4 - 2*a*b*c^3*d + a^2*c^2*d^2)*g*i^3) + 2*b^2*log(b*x + a)/((b^3*c^3 - 3*
a*b^2*c^2*d + 3*a^2*b*c*d^2 - a^3*d^3)*g*i^3) - 2*b^2*log(d*x + c)/((b^3*c^3 - 3*a*b^2*c^2*d + 3*a^2*b*c*d^2 -
a^3*d^3)*g*i^3))

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Fricas [A]  time = 0.555237, size = 1022, normalized size = 4.02 \begin{align*} \frac{6 \, A b^{2} c^{2} - 8 \, A a b c d + 2 \, A a^{2} d^{2} + 2 \,{\left (B b^{2} d^{2} n x^{2} + 2 \, B b^{2} c d n x + B b^{2} c^{2} n\right )} \log \left (\frac{b x + a}{d x + c}\right )^{2} -{\left (7 \, B b^{2} c^{2} - 8 \, B a b c d + B a^{2} d^{2}\right )} n + 2 \,{\left (2 \, A b^{2} c d - 2 \, A a b d^{2} - 3 \,{\left (B b^{2} c d - B a b d^{2}\right )} n\right )} x + 2 \,{\left (3 \, B b^{2} c^{2} - 4 \, B a b c d + B a^{2} d^{2} + 2 \,{\left (B b^{2} c d - B a b d^{2}\right )} x + 2 \,{\left (B b^{2} d^{2} x^{2} + 2 \, B b^{2} c d x + B b^{2} c^{2}\right )} \log \left (\frac{b x + a}{d x + c}\right )\right )} \log \left (e\right ) + 2 \,{\left (2 \, A b^{2} c^{2} -{\left (3 \, B b^{2} d^{2} n - 2 \, A b^{2} d^{2}\right )} x^{2} -{\left (4 \, B a b c d - B a^{2} d^{2}\right )} n + 2 \,{\left (2 \, A b^{2} c d -{\left (2 \, B b^{2} c d + B a b d^{2}\right )} n\right )} x\right )} \log \left (\frac{b x + a}{d x + c}\right )}{4 \,{\left ({\left (b^{3} c^{3} d^{2} - 3 \, a b^{2} c^{2} d^{3} + 3 \, a^{2} b c d^{4} - a^{3} d^{5}\right )} g i^{3} x^{2} + 2 \,{\left (b^{3} c^{4} d - 3 \, a b^{2} c^{3} d^{2} + 3 \, a^{2} b c^{2} d^{3} - a^{3} c d^{4}\right )} g i^{3} x +{\left (b^{3} c^{5} - 3 \, a b^{2} c^{4} d + 3 \, a^{2} b c^{3} d^{2} - a^{3} c^{2} d^{3}\right )} g i^{3}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*((b*x+a)/(d*x+c))^n))/(b*g*x+a*g)/(d*i*x+c*i)^3,x, algorithm="fricas")

[Out]

1/4*(6*A*b^2*c^2 - 8*A*a*b*c*d + 2*A*a^2*d^2 + 2*(B*b^2*d^2*n*x^2 + 2*B*b^2*c*d*n*x + B*b^2*c^2*n)*log((b*x +
a)/(d*x + c))^2 - (7*B*b^2*c^2 - 8*B*a*b*c*d + B*a^2*d^2)*n + 2*(2*A*b^2*c*d - 2*A*a*b*d^2 - 3*(B*b^2*c*d - B*
a*b*d^2)*n)*x + 2*(3*B*b^2*c^2 - 4*B*a*b*c*d + B*a^2*d^2 + 2*(B*b^2*c*d - B*a*b*d^2)*x + 2*(B*b^2*d^2*x^2 + 2*
B*b^2*c*d*x + B*b^2*c^2)*log((b*x + a)/(d*x + c)))*log(e) + 2*(2*A*b^2*c^2 - (3*B*b^2*d^2*n - 2*A*b^2*d^2)*x^2
- (4*B*a*b*c*d - B*a^2*d^2)*n + 2*(2*A*b^2*c*d - (2*B*b^2*c*d + B*a*b*d^2)*n)*x)*log((b*x + a)/(d*x + c)))/((
b^3*c^3*d^2 - 3*a*b^2*c^2*d^3 + 3*a^2*b*c*d^4 - a^3*d^5)*g*i^3*x^2 + 2*(b^3*c^4*d - 3*a*b^2*c^3*d^2 + 3*a^2*b*
c^2*d^3 - a^3*c*d^4)*g*i^3*x + (b^3*c^5 - 3*a*b^2*c^4*d + 3*a^2*b*c^3*d^2 - a^3*c^2*d^3)*g*i^3)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*ln(e*((b*x+a)/(d*x+c))**n))/(b*g*x+a*g)/(d*i*x+c*i)**3,x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{B \log \left (e \left (\frac{b x + a}{d x + c}\right )^{n}\right ) + A}{{\left (b g x + a g\right )}{\left (d i x + c i\right )}^{3}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*((b*x+a)/(d*x+c))^n))/(b*g*x+a*g)/(d*i*x+c*i)^3,x, algorithm="giac")

[Out]

integrate((B*log(e*((b*x + a)/(d*x + c))^n) + A)/((b*g*x + a*g)*(d*i*x + c*i)^3), x)